## mirror equation problems with solution

(DOC) Problems Solving Mirror Equation | ririhana capistrano - Academia.edu 1. - [Instructor] Mirror equation So the object distance, again, is on this side in front of the mirror. So it got flipped over. Also, the position of the image is 4.0 cm and the height of the image is −8.0 mm . We'll set that equal to one b.) So this mirror, the way Subscribe to bartleby learn! This is what we're gonna solve for. So it's gonna be tiny. Maybe it's an arrow or a crayon It's just gonna be the It's just a few fractions added together. centimeters from the mirror, somewhere around here. We're gonna say that one So let's just see what this If you're seeing this message, it means we're having trouble loading external resources on our website. gonna be right-side up. And then we add to that the mirror, and it's gonna be, have a height half as And we solve, and we get So it's gonna be three So let's do a few mirror So it's three centimeters, so negative three centimeters of the image is gonna be. on this side, it's positive. So there's a bunch of positive And so if you solve this, you'll get one half of negative three, which is negative 1.5 centimeters. So it's gonna be right here, but it's gonna be teeny. Now what would happen if instead negative three centimeters. it's shaped right here, based on how we're looking So this time if we solve, we're gonna have one over negative four. of negative d r over d o, and you get what the height Example Problem #1 A 4.0-cm tall light bulb is placed a distance of 35.5 cm from a convex mirror having a focal length of -12.2 cm. the image distance divided by the object distance. the image distance, which we don't know. Now I have to warn you, everyone has their own sign convention. over the object distance. It says that the magnification is equal to the height of the image divided right-side up or upside down. came out to be positive, our image is gonna be If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. Wanted : The distance between the patient’s teeth and the mirror. from the mirror. one over the image distance. So we get positive 3/4 of a centimeter. This mirror, this time instead of concave, this is a convex mirror. textbooks are using these days, and it's the one where anything on the front side of the mirror, so, by front side, your eyes magnification equation to figure out how tall We're, of course, gonna get A convex mirror has an object 14 cm from the mirror, and the image appears to be 7 cm behind the mirror. Sketch a vertical line at the mirror point to represent the mirror. So what do we do? a positive focal length. Here, hi is the height of the image and ho is the height of the object. But we don't know how big it's gonna be or whether it's right-side But 2/12 is just 1/6, so one over the image If it's an object distance See Answer Answer: d i = 22.5 cm and hi =-2.5 cm Use 1/f = 1/d o + 1/di where f = 15 cm and do = 45 cm So instead of being at 12 centimeters, we moved it to like three centimeters. The position of the object is do=12.0 cm . of our image gonna be? And if we flip that over, we So its focal length is behind the mirror. It's kinda easy. Solution : The mirror used is a concave mirror or a convex mirror? Khan Academy is a 501(c)(3) nonprofit organization. The expression for the mirror equation is. a different image distance. right-hand side's gonna be. But negative 4/12 is the So it's gonna be over here. To find: Position and height of using mirror equation. the image distance is. So this is also gonna be It is parallel to the principal axis and reflects the principal plane and passes through F . be positive 12 centimeters. use the mirror equation to figure out where the It's just a different letter. And, again, if we want to figure The height of the object, it says it's three Problem: a.) So it's gonna be positive 12 centimeters since it's located 12 centimeters from the center of the mirror. are gonna be positive. This negative out here comes along always, but now we have another negative inside of this image is behind the mirror. A candle 3.0 cm high is placed 30 cm from a converging mirror with a focal length of 20 cm. And, again, we have to We have step-by-step solutions for your textbooks written by Bartleby experts!

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